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Ruby Ruby Basics (Retired) Ruby Methods Method Returns: Part 2

Posted by ella blue
ella blue
2,252 Points

def mod(a, b) puts "dividing #{a} % #{b}:" return a % b end puts mod(12 % 4)

i have error

def mod(a, b) puts "dividing #{a} % #{b}:" return a % b end puts mod(12 % 4)

method.rb 
def mod(a, b)
  puts "dividing #{a} % #{b}:"
  return a % b
end
puts mod(12 % 4)

2 Answers

Nicholas Hebb
Nicholas Hebb
18,872 Points

You probably just made a typo - but just in case ... when you're calling the function, you need to pass the parameters separated by a comma - without the %. So instead of:

puts mod(12 % 4)

You should have:

puts mod(12, 4)
ella blue
ella blue
2,252 Points
ella blue
ella blue
2,252 Points

thanks :)