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beven nyamande
9,575 Pointsdictionaries
where am i gettign wrong
# You can check for dictionary membership using the
# "key in dict" syntax from lists.
### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2
def members(word,theKey):
return len(word)
1 Answer
Thomas Kirk
5,246 PointsHello,
Your code is only returning the total number of items in your dictionary. The question asks you to return the number of items in your list of keys that can be found in that dictionary.
To do so, you should loop through each item in the list, and check if it can be found in the keys of the dictionary. If the list item is in the dictionary keys, add 1 to a running total, and return that total after the for loop.
Hope that makes sense...
def members(my_dict, my_list):
count = 0 # set a variable, count, as 0, to count number of matches
for item in my_list: # for each item in the list of keys...
if item in my_dict.keys(): # ...check if that item is in the dictionary keys.
count += 1 # if True, add 1 to the variable count
return count # return count, to give the number of matches