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Idris Abdulwahab
Courses Plus Student 2,961 PointsDictionaries
Code challenge: Make a function named word_count. It should accept a single argument which will be a string. The function needs to return a dictionary. The keys in the dictionary will be each of the words in the string, lowercased. The values will be how many times that particular word appears in the string.
My code worked when I tried it in Workspaces but it's not being accepted as a successful try in the code challenge. Please help look at it.
Thank you so much.
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
vibes = string.lower()
new = vibes.split()
roses = {}
for word in new:
occurence = new.count(word)
roses.update({word:occurence})
return (roses)
2 Answers
Stuart McIntosh
Python Web Development Techdegree Graduate 22,874 PointsTry again as I got your code to work!
Abubakar Gataev
2,226 PointsI am not a prof but I think the argument has to be a string.