Dictionary iterations step 4 of 4?

Question

cant figure out how to create the courses function.

teachers.py

# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
my_dict = {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
           'Kenneth Love': ['Python Basics', 'Python Collections']}

def most_classes(my_dict):
  largest = 0
  for key in my_dict:
    if len(my_dict[key]) > largest:
      largest = len(my_dict[key])
      busy_teacher = key
  print(busy_teacher)
  return busy_teacher  
most_classes(my_dict)


def num_teachers(my_dict):
  number = 0
  for key in my_dict:
    number += 1
  return number
num_teachers(my_dict)

def stats(my_dict):
  result = []
  for key in my_dict:
    result.append([key, len(my_dict[key])])
  return result

def courses(my_dict):
  resultz = []
  for course in my_dict:
    resultz.append(my_dict.values())

Answer 1 · 2015-04-23T08:54:48Z

April 23, 2015 8:54am

There is a little bit of wonkiness in a couple places

You're loop is over the teachers not the courses as they are the keys in the dictionary. You need to get the courses out of the lists they are in when they are values in the dictionary. You also appear to be appending all of the values in the dictionary at once multiple times. You also need a return statement.

def courses(my_dict):
  resultz = []
  for teacher in my_dict:
    courses=my_dict[teacher]
    ....
  return resultz

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Cole Diemer

Cole Diemer

Dictionary iterations step 4 of 4?

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Alvin McNair

Alvin McNair