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Kirk Watts
2,202 PointsDid I misunderstand the challenge?
As far as I can tell, my code words and does what is asked of it, but I'm not sure I've properly understood what Kenneth wanted me to do?
As I see it, I expect an itterable (such as the word banana), get a random number between 0 and the length of the itterable -1 (in this case, it'd be between 0 and 5), then return the value of the index of the random number. So, if the random number turned out to be 3, we'd get the letter n back.
# EXAMPLE
# random_item("Treehouse")
# The randomly selected number is 4.
# The return value would be "h"
import random
def random_item(iterable)
number = random.randint(0, len(iterable) - 1)
return iterable[number]
2 Answers
Jeff Wilton
16,646 PointsYou are missing a colon after your function definition,
def random_item(iterable):
but other than that, you are very close.
Indexes start at 0, so ''banana' would index like this:
[0=b, 1=a, 2=n, 3=a, 4=n, 5=a]
Thus 'banana'[3] is 'a' not 'n'.
This is why we go from 0 to the length of the word minus 1 (from 0 to 5 instead of 1-6).
Hope this helps!
Kirk Watts
2,202 PointsDoh! I'll try again. Didn't spot that missing colon :). Thanks!