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Start your free trialAnthony Piscocama
4,328 Pointsdifferent approach
var html = '';
var color = ['red','green','blue']
var rgbColor;
for(var i = 0; i<= 3; i++){
color[i] = Math.floor(Math.random() * 256 );
rgbColor = 'rgb(color)';
html += '<div style="background-color:' + rgbColor + '"></div>';
}
document.write(html);
i got the answer already but was messing around with this, is there anyway to get this to work? or why it wouldnt?
1 Answer
KRIS NIKOLAISEN
54,971 PointsUsing the video workspace the following will produce 3 colored circles:
var html = '';
var color = [0,0,0];
var rgbColor;
for(var i = 0; i < color.length; i++){
color[i] = Math.floor(Math.random() * 256 );
rgbColor = 'rgb(' + color + ')';
html += '<div style="background-color:' + rgbColor + '"></div>';
}
document.write(html);
Some differences:
- color is initialized with numbers instead of strings
- the condition to run was changed to i < color.length. i <= 3 will result in a color with 4 parameters on the final iteration
- color is concatenated in the assignment to rgbColor. Otherwise your color is the string 'rgb(color)'