disemvowel

Question

I've tried this a couple of different ways, such as the code attached, along with attempting to use a try/exempt approach, and though both ways seems that it would return the right word, it's not saying so.  Any helpful hints here would be appreciated, I'm not sure why this code isn't a solution.
```disemvowel.py
vowels = ["a", "e", "i", "o", "u"]
place = 0
def disemvowel(word):   
    while place < 5 :
        if vowels[place] in word.lowercase() :
            word.remove(place)
        else :
            place += 1
return word
```

Jeff Muday · Answer

Your thinking is correct, but Python strings don't have a remove method -- so instead, we use the replace method. And then the extra "gotcha" here is it has to work for both UPPER and lower case.
There are so many ways that this can be done.  Some Python 'studs' may suggest a Lambda Function or a List Comprehension to make it a "one-liner."  Ignore them and do it your way -- you are the one in charge! :-)
```python
vowels = ["a", "e", "i", "o", "u"]
def disemvowel(word):
    # go through all the vowels
    for letter in vowels:
        word = word.replace(letter,'') # replace letter with empty string if lowercase vowel
        word = word.replace(letter.upper(),'') #replace with empty if uppercase vowel
return word
```
Slightly more concise way below.
python
def disemvowel(word):
    vowels = 'AEIOUaeiou'
    for letter in vowels:
        word = word.replace(letter,'')
    return word
`

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Benjamin Guyton

Benjamin Guyton

disemvowel

1 Answer

Jeff Muday

Jeff Muday