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Python Python Collections (2016, retired 2019) Lists Disemvowel

Henry Lin
Henry Lin
11,636 Points
Posted by Henry Lin
Henry Lin
11,636 Points

disemvowel function didn't pass the challenge but worked fine on workspace!

What's wrong with my code? it does the trick that the question describes

disemvowel.py 
def disemvowel(word):

    vowels =['a', 'e', 'i', 'o', 'u']
    result = ''
    for letter in word.lower():
        if not letter in vowels:
            result += letter
    word = result
    return word

3 Answers

Ari Misha
Ari Misha
19,323 Points
Ari Misha
Ari Misha
19,323 Points

Hiya Henry! When question said "be sure to look up for both uppe() and lower() cases", it can mean more than one possible statements. But this is how i'd solve this:

def disemvowel(word):

    vowels =['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']
    result = ''
    for letter in word:
        if not letter in vowels:
            result += letter
    word = result
    return word
Ryan S
Ryan S
27,276 Points
Ryan S
Ryan S
27,276 Points

Hi Henry,

You almost got it, but what happens if "word" contains uppercase letters? Your for loop converts every letter to its lowercase version and stores that in result.

You'll need to find a way to preserve the original case.

Good luck.

Henry Lin
Henry Lin
11,636 Points
Henry Lin
Henry Lin
11,636 Points

Thank you for help, I got it now.

Rodwell Mazambara
Rodwell Mazambara
1,402 Points
Rodwell Mazambara
Rodwell Mazambara
1,402 Points

I am also facing a similar challenge. The code is working fine in workspace but I keep getting an error on the challenge. I can see that I am even preserving case of the initial letters.Here is my code:

    def disemvowel(word):
    vowels=["a","e","i","o","u"]
    word_length=len(word)
    index=0
    wordlist=list(word)

    while(index<word_length):
        if wordlist[index].lower() in vowels:
            del wordlist[index]
        index+=1
        word_length=len(wordlist)

    word=''.join(wordlist)
    return word