Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Niko McCarty
Niko McCarty
4,559 Points

Do not split only on spaces error...

For some reason, my code is not passing for this challenge and I keep getting an error which says "Do not split only on spaces." I cannot continue on in the course until I pass this challenge, unfortunately. Any advice?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    string = string.lower()
    new_string = string.split(' ')
    final = {}
    for key in new_string:
        if key in final:
            final[key] += 1
        else:
            final[key] = 1
    return final

2 Answers

Umesh Ravji
Umesh Ravji
42,386 Points
Umesh Ravji
Umesh Ravji
42,386 Points

You would have to remove the line:

new_string = string.split(' ')

and replace it with

new_string = re.split('\s', string)

or you can also can split without any arguments to get the same result [Edit]: not longer seems to work..

new_string = string.split()
Umesh Ravji
Umesh Ravji
42,386 Points
Umesh Ravji
Umesh Ravji
42,386 Points

You have to split on whitespace.

new_string = re.split('\s', string)
Niko McCarty
Niko McCarty
4,559 Points

Adding this did not work for me.

def word_count(string): string = string.lower() new_string = string.split(' ') new_string = re.split('\s', string) final = {} for key in new_string: if key in final: final[key] += 1 else: final[key] = 1 return final