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Start your free trialVasco Ramalho
1,998 Pointsdocument.querrySelectorAll
selection methods
<!DOCTYPE html>
<html>
<head>
<title>Rainbow!</title>
</head>
<body>
<ul id="rainbow">
<li>This should be red</li>
<li>This should be orange</li>
<li>This should be yellow</li>
<li>This should be green</li>
<li>This should be blue</li>
<li>This should be indigo</li>
<li>This should be violet</li>
</ul>
<script src="js/app.js"></script>
</body>
</html>
let listItems = document.querySelectorAll("rainbow");
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];
for(var i = 0; i < colors.length; i ++) {
listItems[i].style.color = colors[i];
}
2 Answers
Sean T. Unwin
28,690 PointsquerySelector
and querySelectoryAll
parameters need to be prefaced with a dot (.
) for classes and a hash (#
) for an id. If the parameter is not prefaced with one of those characters then the function will assume a tag is given.
Furthernore, you want to be accessing the list items, as opposed to the list as whole, i.e. ('ul').
In this case, we can use querySelectorAll
with li
as the parameter. Now, in a real scenario we don't necessarily want to grab all the li
elements in the page. This takes us back to the first point I made -- use the id selector + rainbow
then a space and finally the tags to grab. This is exactly the same way we could select the same elements in CSS.
Don't forget to enclose it with quotes as the function takes a String.
Dan Weru
47,649 Pointslet listItems = document.querySelectorAll("#rainbow");
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];
for(var i = 0; i < colors.length; i++) {
listItems[i].style.color = colors[i];
}
To select elements with an id, use the # (hash) sign infront of the selector. Also there is no space between i and ++.
Sean T. Unwin
28,690 PointsNot to detract from your answer, but the space after the i
is provided by the challenge and is valid, in that it will be parsed correctly.