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Start your free trialTomasz Grodzki
8,130 PointsDoes this filter method works, at all?
I have broken this code to simpler snippets and it looks like filter method from the solution doesn't work... Take a look at these two codes:
It looks that this first solution that Ashley showed us doesn't work. I get in console every element of array.
class Tokens {
constructor ( dropped ) {
this.dropped = dropped;
}
get unusedTokens(){
return this.dropped.filter(token => !token.dropped);
}
}
const drop = [ false, true, false, true, false, true ];
const newToken = new Tokens ( drop );
console.log ( newToken.unusedTokens );
And just to compare, I did a for loop to filter elements in array and it works!
class Tokens {
constructor ( dropped ) {
this.dropped = dropped;
}
get unusedTokens(){
const newArray = [];
console.log ( this.dropped.length );
for ( let i = 0; i < this.dropped.length; i++ ) {
if ( this.dropped[i] === false ) {
newArray.push ( this.dropped[i] );
}
}
return newArray;
}
}
const drop = [ false, true, false, true, false, true ];
const newToken = new Tokens ( drop );
console.log ( newToken.unusedTokens );
Why the first solution doesn't work?
1 Answer
Steven Parker
231,275 PointsThe code in the video is:
return this.tokens.filter(token => !token.dropped);
It's intended to filter an array of Token objects, using their "dropped" property (and each Token only has one).
But the code above is different:
return this.dropped.filter(token => !token.dropped); //"dropped" instead of "tokens"
This is taking an array of boolean states named "dropped" and attempting to filter each one on it's own "dropped" property, which it does not have.
But your loop indexes the boolean array and tests each one directly, giving a different result.
Tomasz Grodzki
8,130 PointsTomasz Grodzki
8,130 PointsNow I see... I have lost a little. But now everything's clear. Thanks!