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JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops The Refactor Challenge Solution

Posted by hunter bougis
.a{fill-rule:evenodd;}techdegree seal-36
hunter bougis
Full Stack JavaScript Techdegree Graduate 18,367 Points

Does this still work too???

I got it right, but I used a simpler way to get the answer. Could someone please tell me if the way I did it is sufficient or not???? Thanks in advance!

var html = ''; var red; var green; var blue; var rgbColor; var allColors;

for (var i = 0; i <= 10; i += 1) { allColors = red, green, blue, rgbColor, html; allColors = Math.floor(Math.random() * 256); } document.write(html);

2 Answers

Liam Clarke
Liam Clarke
19,938 Points

Hi Hunter

The code you have put doesn't give the same results

within your, for loop, you just assign allColors to all the variables and then assign allColors to the Math.floor

However, it looks like your trying to prevent repeating yourself with the Math.floor, there's a bunch of ways of doing this, you can use arrays, objects, etc

Heres how I would follow DRY coding for the random generation

var html = '',
    rgbColor,
    allColors = {red: "", green: "", blue: ""};

for (var i = 0; i <= 10; i += 1) {
    for (colors in allColors) {
        allColors[colors] = Math.floor(Math.random() * 256);
    }
    rgbColor = `rgb(${allColors.red}, ${allColors.green}, ${allColors.blue})`;
    html += `<div style="background-color: ${rgbColor};"></div>`;
}
document.write(html);

Hope this helps

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,971 Points
KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,971 Points

It doesn't work. Run this through the console and see what you get.

var html = '';
var red;
var green;
var blue;
var rgbColor;
var allColors;

for (var i = 0; i <= 10; i += 1) {
    allColors = red, green, blue, rgbColor, html;
    console.log(allColors)
    allColors = Math.floor(Math.random() * 256);
    console.log(allColors)
}

console.log("HTML = " + html) 
document.write(html);