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PHP PHP Basics Unit Converter Manipulating Numbers

Posted by Santis Smagars
Santis Smagars
980 Points

dont get it ..what is wrong..

Can not figure out what is wrong.

index.php 
<?php

//Place your code below this comment
$integerOne = 1;
$integerOne = 1 + 5;
var_dump ($integerOne);
$integerTwo = 2;
$integerTwo = 2 - 1;
var_dump ($integerTwo);
$floatOne = 1.5;
var_dump ($integerOne * $floatOne);
?>
Santis Smagars
Santis Smagars
980 Points

sorry..it asks me to multiply integer one with float one without changing values. dont understand what they mean by without changing values? i am not changing them..i am simply multiplying them so whats wrong? thx

1 Answer

Nish Patel
Nish Patel
1,103 Points
Nish Patel
Nish Patel
1,103 Points

The task requires you to use += and -= operators. Don't worry hang in there, practice makes perfect!

//Place your code below this comment
//Task 1
$integerOne = 1;
$integerTwo = 2;
//Task 2
$integerOne += 5;
$integerTwo -= 1;
//Task 3
$floatOne = 1.5;
echo $integerOne * $floatOne;
?>
Santis Smagars
Santis Smagars
980 Points

Thx Nish for such fast answer. I thought i will wait for weeks :D . Anyway as you wrote += stuff..i wrote that too earlier..after could not fight 3rd task was just playing around with tasks 1 and2 ..statement about not changing values kinda trapped me in corner.. i guess i focused on that part of question too much. Dont remember in videos about variables and operators that i can simply write arithmetic action just with variables without putting a var_dump before or without creating a new variable for equation to multiply integerone and floatone But maybe i missed somthing. I was thinking to return and try to create new variable..do a equation and then echo it with new variable name. But i guess that would be wrong too. Thx very much again!