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Start your free trialJackson Monk
4,527 PointsDon't know what's wrong
I don't know what's wrong here. It's probably something simple since I don't really have a perfect understanding of AJAX, but help would be appreciated.
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
request.open('GET', 'footer.html');
};
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
<script src="app.js"></script>
</head>
<body>
<div id="main">
<h1>AJAX!</h1>
</div>
<div id="footer"></div>
</body>
</html>
2 Answers
Elijah Quesada
Front End Web Development Techdegree Graduate 32,965 PointsYou should add the request outside of the function
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
};
request.open("GET", "footer.html");
Jackson Monk
4,527 PointsOh lol I thought the end of the function was outside the if brackets but I was still in the function