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Python Python Basics (2015) Letter Game App Even or Odd Loop

Jeff Ness
seal-mask
.a{fill-rule:evenodd;}techdegree
Jeff Ness
Front End Web Development Techdegree Student 8,921 Points
Posted by Jeff Ness
.a{fill-rule:evenodd;}techdegree
Jeff Ness
Front End Web Development Techdegree Student 8,921 Points

Don't know where I went wrong. Testing to see if a random number is even or odd.

Have a feeling that my if statement is incorrect but am unsure.

even.py 
import random


def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start=5

while start > 0:
    num=random.randint(1,99)
    if even_odd(num) is True:
        print("{} is odd".format(num))
    else:
        print("{} is even".format(num))
    start -=1

2 Answers

markmneimneh
markmneimneh
14,132 Points
markmneimneh
markmneimneh
14,132 Points

Hello

try this

import random


def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return  not num % 2 == 0

start=5

while start > 0:
    num=random.randint(1,99)
    if even_odd(num) is True:
        print("{} is odd".format(num))
    else:
        print("{} is even".format(num))
    start -=1

please note the change I made in def even_odd(num):

if ths answers your question, please mark question as answered.