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Start your free trialPhil Ward
4,204 PointsEnhancing a PHP Application - Any idea why this task is failing?
this task is asking for the one item in the array to appear in the html from the foreach loop which loops through the array. I've added the value to the array but the task still fails?
<?php
$recommendations = array();
$recommendations[] = "Avocado Chocolate";
?>
<html>
<body>
<h1>Flavor Recommendations</h1>
<?php
if (!empty($recommendations)) {
echo "<ul>";
foreach($recommendations as $flavor) {
echo '<li> $flavor </li>';
}
echo "</ul>";
} else {
echo '<p>There are no flavor recommendations for you.</p>' ;
}
?>
</body>
</html>
1 Answer
haunguyen
14,985 PointsHi, there seem to be some problem with the backend parsing algo.
Switch out your single quotes for double quotes and it will work.
echo "<li> $flavor </li>";
Phil Ward
4,204 PointsPhil Ward
4,204 PointsThanks so much! i was stuck on the for ages. Still haven't quite worked out when i should be using single quotes versus double quotes in PHP echo but i will get there eventually!