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Python Python Basics (2015) Letter Game App Even or Odd Loop

Drew Greene
Drew Greene
5,086 Points

Even and odd loop

Having trouble with this one. I have tried changing several things and looked through the past questions people have asked but can't figure it out. Any ideas?

even.py
import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start > 0:
    result = even_odd(random.randint(1, 99))
    if result == 0
        print("{} is even".format(result))
    else:
        print("{} is odd".format(result))
    start -= 1
Drew Greene
Drew Greene
5,086 Points

Also, it's telling me that Task 1 is no longer passing

1 Answer

Steven Parker
Steven Parker
230,995 Points

Since it re-checks task 1 first, it says that if there is a syntax error.

In this case it is because there is no colon at the end of the "if" statement.

Fixing that will pass the challenge, but you might want to know that to test something for "truthy" you only need to name it, so you could just write "while start:".

This also goes for testing boolean values, so you could write "if result:".