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Start your free trialClainos Machemedze
1,330 Pointseven odd function
am trying to print five times using while loop but am getting a message ' wrong number of prints'
import random
start = 5
while start < 5:
secret_num = random.randint(1, 99)
if even_odd(secret_num) is True:
print("{} is even.").format(secret_num)
else:
print("{} is odd.").format(secret_num)
start -= 1
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
1 Answer
Dave StSomeWhere
19,870 PointsToo funny, I just made the same mistake on that challenge yesterday.
Double check the 2 print() statements - your syntax error is there (only one character out of place).