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Courses Plus Student 498 Pointseven_odd function
Challenge Task 1 of 1
This one should be short and sweet. Write a function named even_odd that takes a single argument, a number. return True if the number is even, or False if the number is odd. You can use % 2 to find out the remainder when dividing a number by 2. Even numbers won't have a remainder....
PS: i'm a bit sure all that is missing is defining the 'even' or 'odd' numbers; I just can't recollect how to do it and fit into the eve_odd function. See my code below. Thanks
def even_odd(number):
if number == even:
return True
elif number == odd:
return False
1 Answer
Josh Keenan
20,315 PointsHere's the solution
def even_odd(number):
if number % 2 == 0:
return True
else:
return False
get the remainder when divided by two, and if its 0 its even!