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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Megal Rosekrans
Megal Rosekrans
3,497 Points

Even_odd task

Hi guys,

I have been using this code below to print out whether a random number is odd or even. However, the task consistently says that I have entered a wrong number of prints. Can anyone help please?

import random

start = 5

def even_odd(num): while True:

    num = random.randint(1,99)
# If % 2 is 0, the number is even.
    if num % 2 == 0:
        print('{} is even'.format(num))
    else:
        print('{} is odd'.format(num))

start -= 1

# Since 0 is falsey, we have to invert it with not.
return not num % 2
even.py 
import random

start = 5

def even_odd(num):
    while True:

        num = random.randint(1,99)
    # If % 2 is 0, the number is even.
        if num % 2 == 0:
            print('{} is even'.format(num))
        else:
            print('{} is odd'.format(num))

    start -= 1

    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

1 Answer

Steve Hunter
Steve Hunter
57,712 Points

Hi there,

You want your while loop to be outside the even_odd method. Write it after the method.

The while loop runs until start becomes zero. At each loop you're generating a random number and passing it into the even_odd method which returns a true/false answer. You then output the result of that with the strings set in the challenge.

So, without any indenting, after the even_odd method, start the while loop. Generate a random number, like you have done, and store it in something; num is fine.

Then start an if statement passing num to even_odd as a parameter. Then output the even string, else output the odd string. Lastly, decrement start else we'll be here all night!

That all looks like:

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
    num = random.randint(1, 99)
    if(even_odd(num)):
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start -= 1

I hope that helps.

Steve.

Megal Rosekrans
Megal Rosekrans
3,497 Points

Thanks Steve!!!