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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Ethan Koren
Ethan Koren
6,277 Points

even.py

how do i use the even_odd function?

even.py 
import random
start = 5
 def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2


while start = True
    num = random.randint(1, 99)
    even_odd(num): 
        if

1 Answer

dojewqveaq
dojewqveaq
11,393 Points
dojewqveaq
dojewqveaq
11,393 Points

Hi Ethan!

I particularly find this task very confusing, but I'll try to explain as best as I can. You don't need to explicitly say start = True. Here is how it works:

if something: # This already evaluates to True

But this is not crucial, just a little tip ;)

if num % 2 == 0 # This is used to tell if a number is even or odd, if it evaluates to True, than it's even, if evaluates to False,
# it's even.
if not num % 2 == 0 # This is the same thing, but since we used the not, it inverts the result.
# So the function even_odd(num) returns True if num is odd, because it's inverted by the not

Ok, now that we got that out of the way, here is one way to solve this task

import random

 def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start:    
    num = random.randint(0, 99) # Here you generate a random number between 0 and 99
    if even_odd(num): # This evaluates if the function even_odd() passing the argument num is True, if it is, it will execute the following code block
        print("{} is even".format(num))
    else: 
        print("{} is odd".format(num))
    start -= 1 # This statement will decrease the start by 1

I hope this helped! =)