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Ruby

Tom Nunn
Tom Nunn
16,333 Points
Posted by Tom Nunn
Tom Nunn
16,333 Points

Find the Odd Number of Integers in a given Array

When given an Array - through a Method. How can I locate the Integer in the given array which appears an odd amount of times?

i.e

array = [1,1,1,1,1,1,10,1,1,1,1]

So in this array 1 appears 10 times (even), where 10 appears once (odd).

What would be the best way to approach this? I was attempting to use the .each method and a block...

def find_odd_integer(seq)
    seq.each do |odd|
    # Solution
end

1 Answer

gregsmith5
gregsmith5
32,615 Points
gregsmith5
gregsmith5
32,615 Points

I'm not sure if you just want the answer or some hints, so I created a gist for the algorithm linked here. If you want to tackle this yourself, try tracking the number of times an integer appears using a hash, then incrementing the value of each in your each loop. Keep in mind that hash#select and hash#keys are your friends here.

Tom Nunn
Tom Nunn
16,333 Points
Tom Nunn
Tom Nunn
16,333 Points

Cheers Greg! I will have another go later with your hints. Much appreciated.