Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialMisha Shaposhnikov
8,718 PointsFlickr Photos Not Showing
For some reason, I am seeing the gray styling boxes for the images, but the images themselves are not being loaded. I manually entered the image URLs and everything was fine. Then, I chained the fail() method to the end of the $.getJSON() call. Still nothing. If someone could please help me, here is my code from flickr.js:
$(document).ready(function () {
$('button').click(function () {
$("button").removeClass("selected");
$(this).addClass('selected');
var flickrAPI = "http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";
var animal = $(this).text();
var flickrOptions = {
tags: animal,
format: "json"
};
function displayPhotos(data) {
var photoHTML = "<ul>";
$.each(data.items, function (i, photo){
photoHTML += '<li class="grid-25 tablet-grid-50">';
photoHTML += '<a href="' + photo.link + '" class="image">';
photoHTML += '<img scr="' + photo.media.m + '"></a></li>';
}); //end each
photoHTML += '</ul>';
//console.log(photoHTML);
$('#photos').html(photoHTML);
}
$.getJSON(flickrAPI,flickrOptions,displayPhotos).fail(function () {console.log("fail")});
}); //end click
});// end ready
1 Answer
Misha Shaposhnikov
8,718 PointsNevermind, I figured it out. In this line:
photoHTML += '<img scr="' + photo.media.m + '"></a></li>';
I misspelled the "src" attribute. Argh, silly spelling errors.
Dave McFarland
Treehouse TeacherDave McFarland
Treehouse TeacherMisha Shaposhnikov
I do that all the time!