Float, float on - changing function to float before adding

Question

I also tried it as so:
def add(num1,num2):
    return(float(num1 + num2))
AND
def add(num1,num2):
    float()
    return(num1 + num2)
this seems pretty straight forward? What am I doing wrong.
I am converting the arguments into floats before adding. No?
```trial.py
def add(float(num1,num2)):
    return(num1 + num2)
```

Gianmarco Mazzoran · Answer

Hi,
the float function takes only **one argument.
The challenge is asking you to return the floated version of your arguments so you need to do something like this:
python
def add(num1, num2):
    return float(num1) + float(num2)

Jennifer Nordell · Answer

We don't do the conversion of the floats in the definition of the parameters of the function.  Instead we take the float of each number and add it together.  Here's my end code to clarify what they're looking for:
```python
def add(x,y):
  try:
    return float(x) + float(y)
  except ValueError:
    return None
```
Note:  this is for challenge 3 of 3.

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Hanifah W

Hanifah W

Float, float on - changing function to float before adding

2 Answers

Jennifer Nordell

Jennifer Nordell

Gianmarco Mazzoran

Gianmarco Mazzoran