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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by john larson
john larson
16,594 Points

For fun, I did a list version of this challenge, appending a tuple for the word value pair

It wouldn't pass the challenge...but it wasn't intended to. I just wanted to try it with a list instead if a dictionary.

word_list = ["my", "fine", "fine", "pony", "pony", "pony"]
count_list = []

for word in word_list:
    count = word_list.count(word)
    count_list.append((word, count))
print(set(count_list))

1 Answer

Chris Howell
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.a{fill-rule:evenodd;}techdegree seal-36
Chris Howell
Python Web Development Techdegree Graduate 49,702 Points
Chris Howell
.a{fill-rule:evenodd;}techdegree seal-36
Chris Howell
Python Web Development Techdegree Graduate 49,702 Points

Well it wont pass the challenge because the challenge is looking for different requirements, but it definitely is an alternative way of grouping the keywords and counts together using sets/tuples.

My output from your code.

>>> {('fine', 2), ('pony', 3), ('my', 1)}

Now all you need is to wrap it up in a nice function so you can call that function and pass it any list of strings to count and print out. :)