for some reason the challenge doesnt work, even tho it seems i did properly. items = ["abc","xyz","bbb"];

Question

for some reason the challenge doesnt work, even tho it seems i did properly.

breaks.py

def loopy(items):
    for item in items:
        if item[0] is "a":
            continue
        else:
            print item
loopy(items)

Answer 1 · 2016-11-12T22:57:25Z

November 12, 2016 10:57pm

Your code is really close! The code challenge works fine :)

Two errors:

The code challenge automatically calls your function, it just causes an error (it will just say "Bummer!" it wouldn't cause any errors in Python).
You need parentheses for the print function. print in Python 2 and print in Python 3 are different.

You did a great job. It is normal to run into these kind of errors :) Don't worry it happens to everyone.

If you fix those, your code should look like:

breaks.py

def loopy(items):
    for item in items:
        if item[0] is "a":
            continue
        else:
            print(item)

Good luck! ~alex

Answer 2 · 2016-11-12T22:58:14Z

November 12, 2016 10:58pm

Almost ...

You don't need to call loopy, and you need to add parentheses around print (item):

def loopy(items):
    for item in items:
        if item[0] is "a":
            continue
        else:
            print (item)

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