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5,452 PointsFunction max
No idea how to do this.
function max (x, y) {
return x
if ( x > y ) {
alert('amazing');
} else {
alert('sorry, try again');
}
}
1 Answer
Kristiana Georgieva
14,595 PointsHey there!
You definitely have the basics right. Let's break this down.
Since the program doesn't know how to read numbers from strings by itself, you need to use the 'parseInt()' function for both arguments. Once they are read as numbers, the IF statement can really calculate if x > y.
The RETURN function ends the function, so it shouldn't be in the beginning of the function, like in it is in your code. The RETURN doesn't even let your function get to the IF statement.
The condition of the task says "The function should return the larger of the two numbers" meaning that IF x > y, then it should RETURN the biggest number ( if IF is true, then this number is x). For example: If the statement said "if ( parseInt(y) > parseInt(x) )" and y was the bigger number (aka making the IF statement true), then it should return y.
Here's a visual of the code, in case the explanation is confusing:
function max(x, y) {
if ( parseInt(x) > parseInt(y)) {
return x;
} else {
return y;
}
}
Good luck!