Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialKary Powell
1,042 PointsFunction max (not working) {
I have tried this multiple ways but to no ado. I need help...
function max(a, b) {
if (a > b); {
return a;
} else {
return b;
}
}
max (3, 6);
3 Answers
Steven Parker
231,236 PointsYou're really close! But the "if" statement should not have a semicolon between the conditional expression and the open brace of the code block.
Then for task 2, be sure to include your function call as the argument to an alert function call (call inside a call).
Kary Powell
1,042 PointsThanks, guys! That fixed it. I really appreciate the help. It's the little things I haven't solidified yet.
eslam said
Courses Plus Student 6,734 Points-first of all remove ; after the if statement your code should look like this
if (a > b) {
-now you have a function that will return a value but you didn't tell the function to do anything so to print the value of your function to test it out you can use 1 of the 2 methods
console.log(max(3,6));
document.write(max(3,6));