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Python Python Basics (2015) Shopping List App Break

Erik Luo
Erik Luo
3,810 Points
Posted by Erik Luo
Erik Luo
3,810 Points

'function' object is not iterable

What's the problem?

breaks.py 
def loopy(items):
    for items in loopy:
        if items == "STOP":
            break
        print (items)
john larson
john larson
16,594 Points
  • I believe you need to loop through items, not loopy
  • for item in items:
  • items probably represents a list that you will loop over
  • the whole parameter/argument thing takes some getting used to

2 Answers

Alexander Davison
Alexander Davison
65,469 Points

Nice one, John! But, the reason it isn't passing the challenge is because you print the item first, so if the item was "STOP", it would print STOP then quit the loop. The challenge is expecting to break out of the loop immediately, and not print "STOP". Also, for Erik, the reason why your code isn't working is because you said "for items in loopy" (sorry, I do't understand why you did that :/), which won't pass the challenge, so instead you should say "for item in items" (and, when you do that, you should change the if statement's condition to item == "STOP"). This is the final result (which should work):

def loopy(items):
  for item in items:
    if item == "STOP":
      break
    print(item)

Hope this helps for both of you! :) ~Alex

Erik Luo
Erik Luo
3,810 Points
Erik Luo
Erik Luo
3,810 Points

Thank you

Alexander Davison
Alexander Davison
65,469 Points

No problem :)

john larson
john larson
16,594 Points
john larson
john larson
16,594 Points

This works in my editor, but it's not passing the challenge. I don.t know why.

def loopy(items):
    for item in items:
        print(item)
        if item == "STOP":
            break
Erik Luo
Erik Luo
3,810 Points
Erik Luo
Erik Luo
3,810 Points

I think the if has to be before print.

Name:GoogleSearch orJonathan Sum
Name:GoogleSearch orJonathan Sum
5,039 Points
Name:GoogleSearch orJonathan Sum
Name:GoogleSearch orJonathan Sum
5,039 Points

john larson

I saw some1 asked the same question before. Because you put the "If break"statement after printing out all of item of items, the "if break" statement can't check the keyword"STOP" in the items or not. (correct me if i am wrong~~i am still a noob...

items=["a","b","STOP","d"] # there are 4 item in items list.
for item in items:
        print(item)              #printing out item of items
       #a
       #b
       #STOP
       #d
if item =="STOP":   #after printing out all of item of items ,you put the "if break"statement is meaningless. How can the if statement checks which item is STOP after all of item has already printed?
    break