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Start your free trialbronnyreinhardt
1,007 PointsFunctions versus methods
The slide at the end of the Syntax Overview lesson provides the following breakdown of the Objective-C function-call syntax:
type foo = [classinstance instanceMethodwithParam1:param1 andParam2:param2];
which I think alludes to the second function call in main.m ([ball setRadius:25];
):
int main()
{
Sphere *ball = [[Sphere alloc] init];
[ball setRadius:25];
NSLog(@"ball radius %f", [ball radius]);
return 0;
}
So how does andParam2:param2]; figure into this code? Or does it not refer to the example from the lesson?
2 Answers
emanuele menon
Courses Plus Student 790 PointsThe method setRadius: has only one argument. The method declaration should be something like this
- (void)setRadius:(int)radius;
The second parameter shown as example in the function call syntax just don't refer to setRadius: example.
Regards.
bronnyreinhardt
1,007 PointsI've come across something similar in the quiz following the @properties lesson. The question was:
Following is a valid statement to call a method:
[object methodName: paramName];
True or false.
But in the lesson, the method was called like this: [ball setRadius: 25];
Instead of 'paramName', a value is initialized.
Does anybody know what's going on?
bronnyreinhardt
1,007 Pointsbronnyreinhardt
1,007 PointsI think I know what you're saying, Emanuele, but why would the example in the slide include a function call that comprises two parameters? This would appear to go beyond the scope of the lesson.