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Shaun Kelly
5,648 Pointsfunctions with char instead of int
My code doesn't work for some reason and it's printing out the letter f which I don't know why because I haven't used the char 'f' in this situation??
char functionOne(char a, char b, char c);
int main () {
char word = functionOne('h', 'e', 'y');
printf("%c\n", word);
return 0;
}
char functionOne(char a, char b, char c){
return a + b + c;
}
5 Answers
Kyle Adams
5,571 PointsI'm thinking maybe it is because the functionOne method is a char itself, which would only be one character. Try changing that to a string? Also word is a character so that would have to be changed to a string. You are passing in several characters and thus you will either need to create an array of characters or make the return value and the type of word to be string
Shaun Kelly
5,648 Pointscan you provide with an example on how to do the char array with the function ?
Kyle Adams
5,571 Pointsok so I doubt you want to do char array but working with strings would be a bit easier. Change the value of the functionOne to NSString * and you can create a new string in the function with [NSString stringWithFormat:@"%c%c%c", a, b, c]. Then back in main instead of using char word, you would use NSString * word Then also when you are printing out you will want to use %@ instead of %c since you are now using an NSString object
Shaun Kelly
5,648 Pointsi'm working in a c file not objective c so I can't use NSString
Antoine Guenet
2,843 PointsI'd be interested to know the answer as well if you figure it out! Thanks :-)
Shaun Kelly
5,648 PointsThis is the only thing I could come up with but the problem is that it's only carrying one parameter which doesn't solve the problem I stated above.
char function(char a);
int main () {
printf("%c%c%c\n", function('h'), function('e'), function('y'));
return 0;
}
char function(char a){
return a;
}