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Python Python Collections (Retired) Dictionaries Teacher Stats

Posted by Thomas Katalenas
Thomas Katalenas
11,033 Points

give me a hint!?

# going the wrong way with this the only way this would work is if i make the teachers list append sub lists or tupples.
# or some dictionary stuff which is probably the correct answer.

def most_classes(dict_teachers)

teachers = []

max_count = count
teachers.append(teacher)
teachers.append(max_count)
count = 0
for key in dict_teachers:
  count += 1
  teacher = key
  print(dict[key])

2 Answers

qlpxjevhuv
qlpxjevhuv
10,503 Points
qlpxjevhuv
qlpxjevhuv
10,503 Points

Hi Thomas,

The challenge specifies a dictionary for you. You have to define a function called 'most_classes' which takes a dictionary as a formal parameter and returns the name of the teacher with the most classes.

def most_classes(our_dict):
    ...do things...
    return teacher

Next, we need two variables to store 1) the name of the teacher with the most classes and 2) the number of classes they have.

def most_classes(our_dict):
    teacher = ''
    most_classes = 0
    return teacher

We need to loop through the teachers in the dictionary and check the number of classes they have, so we need a for loop.

def most_classes(our_dict):
    teacher = ''
    most_classes = 0

    for teacher in our_dict:
        num_classes = len(our_dict[teacher])  # Pulls out teacher's values and stores it as an int.
        if num_classes > most_classes:
            mostClasses = num_classes
            teacher = teacher

    return teacher
Thomas Katalenas
Thomas Katalenas
11,033 Points
Thomas Katalenas
Thomas Katalenas
11,033 Points

Here is my updated code I thought max(our_dict) would be nice and optimized, returns right for the example dictionary teacher classes. So this works correctly

def most_classes(our_dict):
  count = 0
  max_count = 0
  teacher = max(our_dict)
  for i in our_dict:
    count = len(our_dict[i])
    if count > max_count:
       max_count = count
       if teacher == i:
         return teacher
       else:
         return i

hmm I wonder why this doesn't work because max() would be faster more speedy I think... anyway thats my theory.

def most_classes(our_dict): max_classes = max(our_dict) return max_classes