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Start your free trialtravis ueki
2,102 PointsGiven a list of [a, b, c, d] How can you use .pop() to remove a c and .insert() to place at 0 index in one line of code
The directions say that this can be accomplished in one step. Does anyone have example code to demonstrate this?
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
def new_list():
x = the_list.pop(3)
the_list.insert(1, 0)
new_list()
>
# Update
> - I got the following to work, however, it feels hacky..
the_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
newItem = the_list.pop(3)
the_list.insert(0, newItem)
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsYou have the code, now combine the lines:
newItem = the_list.pop(3)
the_list.insert(0, newItem)
# becomes
the_list.insert(0, the_list.pop(3))
travis ueki
2,102 Pointstravis ueki
2,102 PointsI didn't even think of that! I love python :)...
Much thanks Chris Freeman