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Start your free trialVuk Spasojevic
9,491 PointsGot this code, tested it and it is working, displaying good values just as in example but it is showing Bummer
If someone can please tell my why its not good when program displays good values.
def squared(num):
try:
argument = int(num)
except ValueError:
return num*len(num)
return num*num
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
1 Answer
Kevin Brennan
19,920 PointsHi Vuk,
Have a look at what you are returning if there is no error, you assigned the variable 'num' to the variable 'argument' but you are not using that argument variable at all in your return.
Regards Kevin.
Vuk Spasojevic
9,491 PointsVuk Spasojevic
9,491 PointsThanks Kevin, I forgot about converting string "2" into the integer 2. Changed last line of code and replace "num" with "argument" and everything was ok. Thanks again for help. Best regards