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2,296 PointsHavent been able to figure out most_courses part . Am i completely off ?
Havent got past most_courses part of challenge, been trying about an hour lol.
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
Treehouse_Dict = {'Andrew Chalkey': ['jquery Basics', 'Node.js Basics'],
'Kenneth Love': ['Python Basics', 'Python Collections']}
def num_teachers(Treehouse_Dict):
return int(len(Treehouse_Dict.keys()))
def num_courses(Treehouse_Dict):
number = 0
for num in Treehouse_Dict.values():
number += len(num)
return number
def courses(Treehouse_Dict):
course_list = []
for courses in Treehouse_Dict.values():
for course in courses:
course_list.append(course)
return course_list
def most_courses(Treehouse_Dict):
max_v = max(Treehouse_Dict.values())
for teacher in Treehouse_Dict:
if Treehouse_Dict.values() == max_v:
return teacher
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsYou are approaching this challenge in a unique way, but let's go with it! If the challenge returns Bummer!
it usually means there is a syntax error. In this case, the if
statement does not have a code block to operate on. Perhaps you meant to execute the return
within the if
block.
After indenting the return
statement, the code now runs but gives the incorrect result. The error is because the max_v
value contains the maximum value of the values()
as seen alphabetically! What you want is the max()
of the len()
of the values. Something like max_v = max(len(value) for value in Treehouse_Dict.values())
I threw in some list comprehension
syntax, but you get the idea of how to get the max value. Once you have the correct max_v
, the if
statement needs to compare apples to apples: if len(Treehouse_Dict[teacher]) == max_v
:
Post back if you need more help. Good luck!