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Hussein Almutawa
12,313 PointsHaving a hard time understanding what the question is asking for...packing/unpacking!?
So I am trying to solve the string_factory challenge. Here is the code I came up with, which seems to work for the template given. However, I don't understand why or where to use ** in this code to solve this challenge. The challenge is not accepting my answer.
Where am I going wrong?
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
template = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(diclist):
newlist = [] #new empty list
for dic in diclist: #iterating through the list so that I operate on each ditionary one step at a time
newlist.append("Hi, I'm {name} and I love to eat {food}".format(name=dic["name"],food=dic["food"])) #append the strings in the lists
print(newlist)
return newlist
values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
string_factory(values)
3 Answers
Kenneth Love
Treehouse Guest TeacherWhen we unpack a dictionary, it's turned into key=value pairs. So **{"name": "Garfield"} would be turned into name="Garfield".
Now, looking at your code, where are you using keyword arguments?
Hussein Almutawa
12,313 PointsHey Kenneth - I posed on a different post regarding disemvowel in hopes that you'd reply. My solution seems to be working perfectly fine, but the challenge is not accepting it.
Here is my code for that:
vowels = ['a','e','i','o','u']
def disemvowel(word):
word = word.lower()
wordlist = list(word) #converting string into list
wordlistcopy = wordlist[:] #copy of my original list
for letter in wordlist:
for vowel in vowels:
try:
wordlistcopy.remove(vowel) #removing from copy while looping through original
except ValueError:
pass
word = ''.join(wordlistcopy) #convert list back into string
print(word)
return word
Kenneth Love
Treehouse Guest TeacherWere you told to lowercase the word? Also, remember, list.remove() only removes the first instance it finds of the particular member, so you have to either remove multiple copies multiple times or find a better solution.
Hussein Almutawa
12,313 PointsSo the code I posted works perfectly fine, even with using list.remove() [Yes, it only moves the first instance, but I made the logic so that works to my favor]. BUT my problem was returning the lower case of the passed string! All fixed! Thank you kindly! :D
Hussein Almutawa
12,313 PointsHussein Almutawa
12,313 PointsI'm not using keyword arguments. The challenge was not accepting my answer because I forgot a stupid little exclamation mark at the end of the string! Haha! I thought that we needed to use keyword arguments to solve this, which was the source of my confusion. It's all good now. Thank you Kenneth for your response!
Kenneth Love
Treehouse Guest TeacherKenneth Love
Treehouse Guest TeacherIn the code you posted:
newlist.append("Hi, I'm {name} and I love to eat {food}".format(name=dic["name"],food=dic["food"])) #append the strings in the listsThat
.format(name=dic["name"])bit...name=dic["name"]is a keyword argument :)