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Python Python Basics (2015) Shopping List App Continue

Laknath Gunathilake
Laknath Gunathilake
1,860 Points
Posted by Laknath Gunathilake
Laknath Gunathilake
1,860 Points

Having Trouble Skipping an item

I'm not sure if items.index('a')==0 is the way to solve this problem.

breaks.py 
def loopy(items):
    while True:
       items.index('a')==0:
          continue 
          else: print items

1 Answer

Haider Ali
.a{fill-rule:evenodd;}techdegree seal-36
Haider Ali
Python Development Techdegree Graduate 24,728 Points

Hi, this challenge asks you to loop through items and check if the first letter in each item is equal to 'a'. If so, then continue. However, if not, call the print() function on that item:

def loopy(items):
    for item in items:  #for every item in items
        if item[0] == "a": #checks if the first letter is a
            continue
        else:
            print(item)

You can do this, however, the else block is not necessary since if the first letter is a, it will skip the else block anyways.

Tagging Kenneth Love since there seems to be a mistake on this challenge. It asks you to print out every member in items whereas this does not actually pass the challenge. To pass the challenge you should just print out that item instead of the whole list.

Thanks,

Haider

Kenneth Love
Kenneth Love
Treehouse Guest Teacher
Kenneth Love
Kenneth Love
Treehouse Guest Teacher

Thanks for the feedback. I updated the prompt a little to make it more clear.

Matthew Reisch
Matthew Reisch
5,671 Points
Matthew Reisch
Matthew Reisch
5,671 Points

I had trouble with this question as well. The wording is a little ambiguous. Perhaps it should be reworded so that it is obvious that the items list is filled with strings and that we are checking the substring (in this case index 0) of each string item for the existence of the character 'a'.

Overall great course experience so far, but this question was not easy to decipher.

Best, Matt