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2,143 Pointshaving trouble with this question ,any ideas ?!
The method below checks the speed of a car and returns a string value: either "safe" or "unsafe". Return "safe" if: The car_speed passed in as an argument is greater than or equal to the number 40. The car_speed passed in as an argument is less than or equal to the number 50. Otherwise, return "unsafe". Hint: You should use the && logical operator to accomplish this task. :)
def check_speed(car_speed)
# write your code here
print "what is your speed?"
car_speed = gets.chomp.to_i
if ( car_speed >= 40 ) && ( car_speed <= 50 )
puts "safe"
end
else
puts "unsafe"
end
6 Answers
Ellis Briggs
11,108 PointsUse another if statement instead of an else, if you are using else, it counts as the end of the first if.
Alex Therin
4,415 Pointsdef check_speed(car_speed) print "what is your speed?" car_speed = gets.chomp.to_i if ( car_speed >= 40 ) && ( car_speed <= 50 ) puts "safe" if ( car_speed <= 50 ) && ( car_speed >= 40 ) puts "unsafe" end
Ellis Briggs
11,108 PointsSorry I have no idea what I was thinking, try putting return instead of puts.
Ellis Briggs
11,108 PointsOh just seen that you put an end after the first 'if' should probably look like :
def check_speed(car_speed)
# write your code here
print "what is your speed?"
car_speed = gets.chomp.to_i
if ( car_speed >= 40 ) && ( car_speed <= 50 )
return "safe"
else
return "unsafe"
end
martinaraignee
12,786 Pointsdef check_speed(car_speed) print "what is your speed?" car_speed = gets.chomp.to_i if (car_speed >= 40) && (car_speed <= 50) puts "safe" elsif (car_speed < 40) && (car_speed > 50) puts "unsafe" end end
for some reasons doesn't work. Could you help, please
Ellis Briggs
11,108 PointsUse return instead of puts as you are returning the final value to the function rather then displaying it.