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Sergio Lopez
13,088 PointsHello. I am totally lost in this challenge. I have a rough idea of how to proceed but i can't get it right.
So i start assigning the string to a variable:
mystring = "this is not what this is"
Then define the function with mystring as an argument
def word_count(mystring):
inside the function, convert the string into a list and set a counter for the repeated words
mylist = mystring.split() counter = 0
so far, so good. Now, here is the beginning of my confussion; for word in mylist: if word is in mylist counter += 1 mydict [word] = counter
I know my problem is in my logic, somewhere within my function.
Can you help me?
Thank you.
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
1 Answer
Kenneth Love
Treehouse Guest TeacherYou probably don't want a counter outside of your loop. When the first word shows up, your counter goes to 1. What does it do for the second word?
Instead, start with a dictionary that'll hold the words and how many times they shown up. If the word isn't in the dictionary, add it and set the value to 1 (since you've now seen it 1 time). If it's already there, add 1 to the word's current value in the dict.