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Start your free trialAndrew McCombs
4,309 PointsHelp - Challenge task 3 of 7
This third-party library gives you access to create a PalprimeChecker object. Create a variable called $checker and assign it a new PalprimeChecker object as the value.
Bummer! It looks like you have not created a variable named $checker....
<?php
require_once("class.palprimechecker.php");
$checker -> $palprimechecker;
echo "The number ## ";
echo "(is|is not)";
echo " a palprime.";
?>
1 Answer
Andrew Dushane
9,264 PointsTo create an instance of a class you use the new keyword.
<?php
$checker = new PalprimeChecker();
?>
ought to do it.
Andrew McCombs
4,309 PointsAndrew McCombs
4,309 PointsThank you