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9,577 PointsHelp me please.
I feel like it is right but it doesn't work? Help please. Thank you in advance.
$.get("footer.html", function(response) {
var $footer = $('#footer');
$('#footer').html();
});
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
</head>
<body>
<div id="main">
<h1>AJAX with jQuery</h1>
</div>
<div id="footer"></div>
<script src="jquery.js"></script>
<script src="app.js"></script>
</body>
</html>
1 Answer
Jennifer Nordell
Treehouse TeacherStill soooo close! Keep in mind that for challenges it's best to not do anything that they don't explicitly ask for. Here you've tried to set up a new variable and assign the footer to it. But then you never use the variable. And the second line inside the block is almost perfect! All it needs is the response from the server. Take a look and see if you can see what I mean:
$.get("footer.html", function(response) { //use get method to get the footer.html and the server response
$('#footer').html(response); // select the footer and use the html method and send the response into the method
});
Happy coding!