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Start your free trialshree sri
540 Pointshelp me to resolve
def repeat(string, times) fail "times must be 1 or more" if times < 1 counter = 0 loop do string = "shree" puts string if counter == 1 break end end end
def repeat(string, times)
fail "times must be 1 or more" if times < 1
counter = 0
loop do
string = "shree"
puts string
if counter == 1
break
end
end
end
2 Answers
elk6
22,916 PointsHi Shree,
Couple of things wrong:
- You are not printing
- You are inputting an incorrect string
- You are not incrementing counter, so it will stay 0 forever
- You are not comparing counter with times ( both vars ) to break out of the loop
Try your code like this
def repeat(string, times)
fail "times must be 1 or more" if times < 1
counter = 0
loop do
print string
counter += 1
if counter == times
break
end
end
end
andynguyen9
1,629 PointsWhy there are 3 ends?
What is "fail" here? Search the net revealed that it is a Kernel method like puts=> don't understand.
fail "times must be 1 or more" if times < 1 => don't understand.
Thank you.