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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Diwakar Singh
Diwakar Singh
Courses Plus Student 1,621 Points

help me with wordcuont.py

wordcount

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word-count(**string):
    return string.lower()

1 Answer

William Harrison
William Harrison
9,585 Points
William Harrison
William Harrison
9,585 Points

First your function is not defined correctly, and the function should be pass a string.

def word_count(parse_string):

Then you will need to set a dictionary variable for your count. Next you will need to split the incoming string into single words.

dict_count = {}  
word_split = parse_string.split()

Then you will need to loop through the word and count them. I do not believe I did this the best way, but it works.

for item in word_split:
        try:
            dict_count[item.lower()] += 1
        except KeyError:
            dict_count[item.lower()] = 1

And finally return the results.

return dict_count