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Start your free trialLuis Miguel Hernandez
4,266 PointsHelp whit the return!
I tried the code in my local environment and it works, please help me
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(text):
dictionary = {}
word_list = text.lower().split(' ')
for letter in word_list:
try:
count = dictionary[letter] + 1
dictionary.update({letter:count})
except:
dictionary.update({letter:1})
return dictionary
1 Answer
Andrey Misikhin
16,529 PointsUse .split() to remove all whitespaces, for example, check this in your variant first: "Bla bla bla".
word_list = text.lower().split()
Luis Miguel Hernandez
4,266 PointsLuis Miguel Hernandez
4,266 PointsPerfect! :) Thank you.