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Razvan Tamasanu
1,873 PointsHelp with a challange
Hi, This is my code: var temperatures = [100,90,99,80,70,65,30,10]; for (i=0; i<1; i++){ temperatures.sort(function(a, b){ return b - a; }); }; console.log(temperatures);
It is working in chrome console, but when I am submitting the work I got an error saying that the results were not in order..
Thank you.
var temperatures = [100,90,99,80,70,65,30,10];
for (i=0; i<1; i++){
temperatures.sort(function(a, b){
return b - a;
});
};
console.log(temperatures);
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
1 Answer
KRIS NIKOLAISEN
54,971 PointsYou have made this more complex than need be. Sorting isn't necessary. You only need to log the temperatures to the console inside the loop.
Razvan Tamasanu
1,873 PointsRazvan Tamasanu
1,873 Pointsi don t think i understood. i have this code now: var temperatures = [100,90,99,80,70,65,30,10]; for (i=0; i<1; i++) { console.log(temperatures); }
and the error is: Bummer: The items in the array weren't logged out in order. Your should log all the temperatures in order, starting at 100 and ending at 10.
in google chrome console everything is ok.. thank you