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Start your free trialMohammad Syed Raihaan
1,358 PointsHelp with 'exiting' objective.
I don't understand what the problem is here. Can someone explain to me what's wrong and what this task expects me to do?
import sys
a=str(input("Do you want to start the movie?"))
if a == "n" or "N":
sys.exit()
else:
print("Enjoy the show!")
1 Answer
cb123
Courses Plus Student 9,858 PointsYour statement always evaluates to true.
if a == "n" or "N": As "N" is not evaluated against anything Python seems to interpret always as True, so you will never get to False. If you go to python console in workspace you can confirm with bool() expressions to confirm results.
As a hint using the lower() or upper() function could be one way of simplifying the logic without using and/or for this challenge. The other way is making sure your "N" is compared to something.
Cooper Runstein
11,850 PointsCooper Runstein
11,850 PointsRight now your if statement is asking if a is equal to "n", or, if "N" is true. You're not actually asking if a == "N", only if it equals "n". The statement if "N" will return true, so your code is always ending at sys.exit(). To fix this, ask:
if a == "n" or a == "N":