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Python Python Collections (Retired) Dungeon Game Random Choices

Posted by Enas Sterjanaj
Enas Sterjanaj
113 Points

help with iterables

I made the following function which seems to work with just having the function take n for the integer. Do i have to pass an itterable into the function to pass this section? How exactly do i do that?

Here is my code:

import random

n = int(raw_input("Please enter number of items to create: "))

def nchoices(n): L = [] my_list = range(n) for item in my_list: L.append(random.choice(my_list))

print(L)
return L

nchoices(10)

choices.py 
import random


#n = int(raw_input("Please enter number of items to create: "))

def nchoices(n):
    L = []
    my_list = range(n)
    for item in my_list:
        L.append(random.choice(my_list))

    print(L)
    return L

nchoices(10)

1 Answer

Dan Johnson
Dan Johnson
40,533 Points
Dan Johnson
Dan Johnson
40,533 Points

Yes, the iterable argument is required. It's needed since you're actually selecting choices from the iterable that is passed in, rather than a range. The integer argument represents how many times you want to randomly pick from the iterable that was passed in.

You don't have to change much with your code to get it to work:

def nchoices(iterable, n):
    # I'd recommend against 'L' as a variable name in most cases
    choices = []

    for item in range(n):
        # Select from the iterable
        choices.append(random.choice(iterable))

    return choices
Enas Sterjanaj
Enas Sterjanaj
113 Points

thanks for clearing this up.