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Devin Scheu
66,191 PointsHelp With Php Conditionals
Question: PalprimeChecker objects have a method called isPalprime(). This method does not receive any arguments. It returns true if the number property contains a palprime, and it returns false if the number property does not contain a palprime. (Tip: 17 is not a palprime.) Turn the second echo statement into a conditional that displays “is” or “is not” appropriately. The conditional should call the isPalprime method of the $checker object. If the isPalprime method returns true, then echo “is”; otherwise, echo “is not”.
My Code:
<?php
include("class.palprimechecker.php");
$checker = new PalprimeChecker();
$checker->number = 17;
echo "The number " . $checker->number . " ";
if ($checker === true){
echo "is"
}
else {
echo "is not"
}
echo " a palprime.";
?>
2 Answers
Jason Anello
Courses Plus Student 94,610 PointsHi Devin,
You need to call the isPalprime() method on the $checker object. That method is what will return true or false. You also need to end your echo statements inside the if/else block with semi-colons.
if ($checker->isPalprime()){
echo "is";
}
else {
echo "is not";
}
`
kevin jordan
11,353 PointsHey Devin -
Pretty sure you have a type error going on. That is when using === instead of ==, you are checking for type AND value. Therefor $checker will never be equivalent to true because true is a boolean and $checker is a PalPrimeChecker object.
Hope this gets you going !! kj