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Matthew Smart
12,567 Pointshelp with php objects
PalprimeChecker objects have a property called number. This task has two parts. First, assign that property a value of 17. Second, remove the two hash signs (##) in the first echo statement and instead concatenate the value of this number property. (Be sure to preserve the space after the two hash signs by concatenating a space after the number.)
this is my code....
<?php
include ('class.palprimechecker.php');
$checker = new PalprimeChecker();
$checker -> number(17);
echo "The number " . $checker . " " ; echo "(is|is not)"; echo " a palprime.";
?>
help please?
3 Answers
David Kaneshiro Jr.
29,247 PointsThe only problem I can see at the moment is the line where you assign the value 17 to the number property. Use the "=" assignment operator instead of encasing it in parenthesis (). In this example, the number property is a variable stored within the object so you can assign a value to it using the "=" operator.
Jason Anello
Courses Plus Student 94,610 PointsAs David mentioned you want to use $checker->number = 17;
Also, you're not echoing out that number but trying to echo the object instead.
include "class.palprimechecker.php";
$checker = new PalprimeChecker();
$checker->number = 17;
echo "The number " . $checker->number . " ";
echo "(is|is not)";
echo " a palprime.";
Syed Mahmoodi
4,744 PointsIf you read the question couple of times (each sentence) you can figure out.
<?php
include ("class.palprimechecker.php");
$checker = new PalprimeChecker(); $checker->number = 17; //adding proper syntax for creating object
echo "The number " . $checker->number . " "; //calling the proper object echo "(is|is not)"; echo " a palprime.";
?>