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Python Python Basics (2015) Logic in Python Try and Except

Himaja Mandla
Himaja Mandla
371 Points
Posted by Himaja Mandla
Himaja Mandla
371 Points

help with the code?

def add(numb1,numb2): addi=numb1+numb2 return(addi) try: #num1=float(input("give me the first number: ")) #num2=float(input("give me the second number: ")) add(float(numb1),float(numb2)): except ValueError: return() else: return(addi)

there is a mistake in the code. I couldn't find it. Can someone help me in this regard?

trial.py 
def add(numb1,numb2):
    addi=numb1+numb2
    return(addi)
try:
    #num1=float(input("give me the first number: "))
    #num2=float(input("give me the second number: "))
    add(float(numb1),float(numb2)):
except ValueError:
        return()
else:
        return(addi)

1 Answer

Clayton Perszyk
MOD
Clayton Perszyk
Treehouse Moderator 48,850 Points
Clayton Perszyk
Clayton Perszyk
Treehouse Moderator 48,850 Points

Hi Himaja,

There are a few things that you need to fix:

  1. There is a stray semicolon when you call add.
  2. The try/except/else code goes inside the add function.
  3. You're using return like a function in the except/else clauses and calling it, when you should be returning values.
  4. You wont need to call add within your add function (it will cause infinite recursion, i.e., a stack overflow).
  5. The commented out code in your solution is unnecessary.

Hope this helps.